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One of the most important ways in which a metric is used is in approximation. Given a function f, finding a sequence which converges to f in the metric d
is called uniform approximation. The most important result in this area is due to the German mathematician Karl Weierstrass (1815 to 1897).
Definition
If f and g are suitable functions on R, then the convolution f * g is the function defined by f * g(x) =
f(x - t) g(t) dt (suitable means ensuring that the integral exists).
This concept of convolution is important in the theory of Laplace transforms among other places.
It turns out that the set X of suitable functions is than a ring under the operations + and * in much the same way that X forms a ring under the usual addition and multiplication.
The Laplace transform
is then a ring homomorphism from (X + *) to (X + .)
That is:
(f + g) =
(f) +
(g) and
(f * g) =
(f).
(g).
Thinking about convolution as an algebraic operation, we may ask: Is there an identity element for this operation?
The answer is: Almost!
The English mathematician Paul Dirac (1902 to 1984) one of the most important founders of Quantum Mechanics, invented the
-function.
This is a "function" with the properties:
(x) = 0 if x
0 and
(x) dx = 1.
You should think of it as "The density function of a unit mass or charge at the origin".
Of course it is not really a function since we would have to have
(0) =
in a rather special way, but it turns out that provided one only uses it in integrals everything is OK.
For example, f *
(x) =
f(x - t)
(t) dt = f(x) since
(t) = 0 except at t = 0.
What we will now do is find a sequence of functions (Kn) which approximate the
-function. The sequence (Kn* f) will then approximate
* f = f.

Definition
The n-th Landau kernel function Kn= cn(1 - x2)n for x
[-1, 1] and 0 otherwise, where cn is chosen so that
Kn = 1.
Here are graphs of some of these functions:
Note that these are the graphs of the density functions of unit masses concentrated on smaller and smaller areas.
Lemma
If f is a continuous function on the interval [-1, 1] then Kn * f is a polynomial.
Proof
Kn* f(x) =
Kn(x - t)f(t) dt and Kn is a polynomial and so Kn(x - t) can be expanded as g0(t) + g1(t) = ... + g2n(t)x2n and so the integral is a polynomial in x.
Lemma
The sequence (Kn * f)
f in d
.
Proof
We need to show that Kn has "most of its area" concentrated near x = 0.
First we estimate how big cn is:
(1 - t)2)ndt = 2
(1 - t)n(1 + t)ndt
2
(1 - t)ndt = 2/(n+1).
Since
Kn= 1 we must have cn
(n+1)/2.
[In fact, cn grows like a multiple of
n. For large n, cn is approximately 0.565
n.]
Look at the area under Kn which is not near 0.
Kn(t) dt =
cn(1 - t2)ndt
(n+1)/2
(1 -
2)ndt
since Kn is decreasing on [
, 1] and this is (n + 1)/2 (1-
2)n(1-
).
If r = 1 -
2 then (n + 1)rn--> 0 as n
.
We are told that f is continuous and by a theorem we will prove in the next section we may assume that f is bounded by M (say).
If x
[0, 1] then given
> 0 we can find
> 0 such that if |t| <
then |f(x - t) - f(x)| <
.
So now look at the convolution : Kn* f.
|f(x) - Kn* f(x)| =
|f(x) - f(x - t)| Kn(t) dt =
+
+
.
Now on [-1, -
] and on [
, 1] we have Kn(t) is small if we choose
small. In fact, we can choose
so that Kn(t) <
/M here and then the first and third integrals are <
.
For the middle integral,
|f(x) - f(x - t)|Kn(t) dt

Kn(t) dt <
since
Kn(t) dt = 1.
Thus |f(x) - Kn* f(x)| is small when n is large and we have our convergence. This completes the proof of the Weierstrass approximation theorem.


|x| with a graph:
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